# `Refl ≡ loop` is empty - Defining `flipPath` via Univalence In this part, we will define the path `flipPath : Bool ≡ Bool`. Recall the picture of `doubleCover`. (Insert gif.) This means we need `flipPath` to correspond to the unique non-identity permutation of `Bool` that flips `true` and `false`. We proceed in steps : 1. Define the function `Flip : Bool → Bool`. 2. Promote this to an isomorphism `flipIso : Bool ≅ Bool`. 3. We use _univalence_ to turn `flipIso` into a path `flipPath : Bool ≡ Bool`. The univalence axiom asserts that paths in `Type` - the space of spaces - correspond to homotopy-equivalences of spaces. As a corollary, we can make paths in `Type` from isomorphisms in `Type`. ## The function - In `1FundamentalGroup/Quest0.agda`, navigate to : ```agda Flip : Bool → Bool Flip x = {!!} ``` - Write `x` inside the hole, and do `C-c C-c` with your cursor still inside. You should now see : ```agda Flip : Bool → Bool Flip false = {!!} Flip true = {!!} ``` This means : the space `Bool` is made of two points `false, true` and nothing else, so to map out of `Bool` it suffices to find images for `false` and `true` respectively. - Since we want `Flip` to flip `true` and `false`, fill the first hole with `true` and the second with `false`. - To check things have worked, try `C-c C-d`. (`d` stands for _deduce_.) Then `agda` will ask you to input an expression. Enter `Flip`. In the `*Agda Information*` window, you should see ```agda Bool → Bool ``` This means `agda` recognises `Flip` as a well-formulated term and is a point in the space of maps from `Bool` to `Bool`. - We can also ask `agda` to compute outputs of `Flip`. Try `C-c C-n` (`n` stands for _normalise_), `agda` should again be asking for an expression. Enter `Flip true`. In the `*Agda Information*` window, you should see `false`, as desired. ## The isomorphism - Navigate to ```agda flipIso : Bool ≅ Bool flipIso = {!!} ``` - Write `iso` in the hole and refine with `C-c C-r`. You should now see ```agda flipIso : Bool ≅ Bool flipIso = iso {!!} {!!} {!!} {!!} ``` - Check that `agda` expects functions `Bool → Bool` to go in the first two holes. These are the maps back and forth which constitute the isomorphism, so fill them with `Flip` and its inverse `Flip`. - Check the goal of the next two holes. They should be ```agda section Flip Flip ``` and ```agda retract Flip Flip ``` This means we need to prove `Flip` is a right inverse and a left inverse of `Flip`. - Write the following so that your code looks like ```agda flipIso : Bool ≅ Bool flipIso = iso Flip Flip s r where s : section Flip Flip s b = {!!} r : retract Flip Flip r b = {!!} ``` The `where` allows you to make definitions local to the current definition, in the sense that you will not be able to access `s` and `r` outside this proof. Note that what follows `where` must be indented.
Skipped step
- To find out why we put `s b` on the left you can try
```agda
flipIso : Bool ≅ Bool
flipIso = iso Flip Flip s r where
s : section Flip Flip
s = {!!}
r : retract Flip Flip
r = {!!}
```
- Check the goal of the hole `s = {!!}` and try using `C-c C-r`.
It should give you `λ x → {!!}`.
This says it's asking for some new proof for each `x : Bool`.
If you check the goal you can find out what proof it wants
and that `x : Bool`.
- To do a proof for each `x : Bool`, we can also just stick
`x` before the `=` and do away with the `λ`.
Tips
You need to case on what `b` can be.
Then for the case of `true` and `false`,
try `C-c C-r` to see if `agda` can help.
The added benefit of having `b` before the `=`
is exactly this - that we can case on what `b` can be.
This is called _pattern matching_.