added 1FundamentalGroup

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Jlh18 2021-09-14 18:12:03 +01:00
parent bc6622c045
commit 682017ab75
5 changed files with 98 additions and 4 deletions

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module 1FundamentalGroup.Quest0 where
open import Cubical.Core.Everything
open import Cubical.Data.Empty
open import Cubical.Foundations.Prelude
open import Cubical.Foundations.Path
open import Cubical.Foundations.GroupoidLaws
data : Type where
base :
loop : base base
¬ : Type Type
¬ A = A
doubleCover : type
doubleCover = ?
refl≢loop : ¬ ( refl loop )
refl≢loop h = {!!}

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Whoa very cool
=======================
In this series of quests we will prove that the fundamental group
of `S¹` is ``.
In fact, our strategy will also show that the higher homotopy groups of
`S¹` are all trivial.
We begin by formalising the problem statement.
## The Circle
A contruction of 'the circle' is :
- a point
- an edge from that point to itself
Here is our definition of the circle in `agda`.
```agda
data S¹ : Type where
base : S¹
loop : base ≡ base
```
The `base \== base` is the _space of paths from `base` to `base`_.
An "edge" is the same as a path.

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Fundamental Group of S¹
================
Prerequisites :
- circle
- loop space
- have useless maps S¹ → and → S¹
- we make helix from
-
Motivating Steps :
0. After sufficient pondering, you guess that
loops are determined by how many times they go around
1. Count number of times loops go around using
by setting the single loop to +1.
2. You can make a comparison maps between loop space and
but can't yet show an equivalence
3. You realize you need to use the definition of S¹,
so you go from `base ≡ base ≃ Z` to `base ≡ x ≃ Bundle x`.
i.e. You try to make the equivalence _over_
Random thought :
to prove `a = b`, we realise that `a = f(x0)`
and `b = g(x0)` for `x0 : X`,
and instead show `(x : X) → f x = g x`.
This turns out to be easier since we now get
access to the recursor of `X`.

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+ Membership not the same as :
+ typing is unique (doesn't make sense to intersect two types)
+
+ Though set theory had fewer axioms type theory's assumptions are more intuitive (hence intionistic type theory)
There is no fiddling about with membership to construct things e.g. cartesian product
+ 'we cannot use LEM' ~ not assuming law of excluded middle _globally_ means type theory theorems are stronger!
+
+ Though set theory had fewer axioms type theory's assumptions are
more intuitive (hence intionistic type theory).
There is no fiddling about with membership to construct things
e.g. cartesian product
+ 'we cannot use LEM' ~ not assuming law of excluded middle _globally_ means
type theory theorems are stronger!
** Fundamental group of S1
+ def of S¹
+ a bunch of stuff about
+ isoToPath to make
+ subst
+ funExt
+ set-truncation
+ paths as equality

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