diff --git a/1FundamentalGroup/Quest1.agda b/1FundamentalGroup/Quest1.agda
index 597585a..d57edd7 100644
--- a/1FundamentalGroup/Quest1.agda
+++ b/1FundamentalGroup/Quest1.agda
@@ -7,7 +7,7 @@ open import Cubical.Data.Int
open import Cubical.Data.Empty
open import Cubical.Foundations.Prelude
open import Cubical.Foundations.HLevels
-open import 1FundamentalGroup.Quest0 using ( Refl ; Refl≢loop )
+open import 1FundamentalGroup.Quest0Solutions using ( Refl ; Refl≢loop )
Ω : (A : Type) (a : A) → Type
Ω A a = a ≡ a
diff --git a/1FundamentalGroup/Quest1Part0.md b/1FundamentalGroup/Quest1Part0.md
index 769aecd..28cc407 100644
--- a/1FundamentalGroup/Quest1Part0.md
+++ b/1FundamentalGroup/Quest1Part0.md
@@ -77,6 +77,10 @@ Try giving it '`loop n times`' composed with `loop`.
Then try to also define the map on the negative integers.
You will need to invert paths using `sym`.
+```agda
+sym : x ≡ y → y ≡ x
+```
+
Looking up definitions
diff --git a/1FundamentalGroup/Quest1Part1.md b/1FundamentalGroup/Quest1Part1.md
index d000a1a..b0d4482 100644
--- a/1FundamentalGroup/Quest1Part1.md
+++ b/1FundamentalGroup/Quest1Part1.md
@@ -1,8 +1,9 @@
-
+# Homotopy Levels
The loop space can contain higher homotopical information that
the fundamental group does not capture.
For example, consider `S²`.
+
```agda
data S² : Type where
base : S²
@@ -32,7 +33,7 @@ So `base ≡ base` has non-trivial path structure.
Let's be more precise about homotopical data :
@@ -81,6 +82,11 @@ In the cubical library we have the result
isProp→isSet : (A : Type) → isProp A → isSet A
```
+which we will not prove.
+Assuming `¬isSetS¹`, use `isProp→isSet` to deduce `¬isPropS¹`.
+
+
+
HLevel
@@ -90,27 +96,21 @@ Generalisation to HLevel and isHLevel n → isHLevel suc n??
-
-which we will not prove.
-Use `isProp→isSet` to conclude `¬isPropS¹` (using `¬isSetS¹`),
-from now you should fill in the hypotheses of the proof yourself
-(put `h` before the `=` sign or use `C-c C-r`).
-
Turning our attention to `¬isSetS¹`,
-again supposing `h : isSet S¹` -
+again given `h : isSet S¹` -
a map continuously taking each pair `x y : A`
to a point in `isProp (x ≡ y)`.
We can apply `h` twice to the only point `base` available to us,
obtaining a point of `isProp (base ≡ base)`.
-Can we map this into the empty space?
+Try mapping from this into the empty space.
Hint 0
We have already shown that `Refl ≡ loop` is the empty space.
-We have imported `Quest0` for you, so you can just quote the
-result from there.
+We have imported `Quest0Solutions.agda` for you,
+so you can just quote the result from there.
diff --git a/1FundamentalGroup/Quest1Part2.md b/1FundamentalGroup/Quest1Part2.md
new file mode 100644
index 0000000..4e847b3
--- /dev/null
+++ b/1FundamentalGroup/Quest1Part2.md
@@ -0,0 +1,3 @@
+# Set Truncation and Higher Homotopy Groups
+
+We've seen what it means for a space to be a "set".
diff --git a/1FundamentalGroup/Quest2Part0.md b/1FundamentalGroup/Quest2Part0.md
new file mode 100644
index 0000000..e7b19ec
--- /dev/null
+++ b/1FundamentalGroup/Quest2Part0.md
@@ -0,0 +1,19 @@
+# Comparison maps between `Ω S¹ base` and `ℤ`
+
+In `Quest1` we have defined the map `loop_times : ℤ → Ω S¹ base`.
+Creating the inverse map is difficult without access to the entire circle.
+Similarly to how we used `doubleCover` to distinguish `refl` and `base`,
+the idea is to replace `Bool` with `ℤ`,
+allowing us to distinguish between all loops on `S¹`.
+
+The plan is :
+
+- Define a function `sucℤ : ℤ → ℤ` that increases every integer by one
+- Prove that `sucℤ` is an isomorphism by constructing
+ an inverse map `predℤ : ℤ → ℤ`.
+- Turn `sucℤ` into a path `sucPath : ℤ ≡ ℤ` using `isoToPath`
+- Define `helix : S¹ → Type` by mapping `base` to `ℤ` and
+ a generic point `loop i` to `sucPath i`.
+- Use `helix` and `endPt` to define the map `base ≡ x → helix x`
+ on all `x : S¹`, in particular giving us `Ω S¹ base → ℤ`
+ when applied to `base`.
diff --git a/_build/2.6.3/agda/1FundamentalGroup/Quest0Solutions.agdai b/_build/2.6.3/agda/1FundamentalGroup/Quest0Solutions.agdai
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